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0=2x^2+6-3x
We move all terms to the left:
0-(2x^2+6-3x)=0
We add all the numbers together, and all the variables
-(2x^2+6-3x)=0
We get rid of parentheses
-2x^2+3x-6=0
a = -2; b = 3; c = -6;
Δ = b2-4ac
Δ = 32-4·(-2)·(-6)
Δ = -39
Delta is less than zero, so there is no solution for the equation
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